Total | Debut | Latest |
---|---|---|
30 | 12/28/1998 | 4/25/2018 |
Sun | Mon | Tue | Wed | Thu | Fri | Sat |
---|---|---|---|---|---|---|
1 | 8 | 10 | 8 | 3 | 0 | 0 |
Circle | Scrab | Debut | Fresh |
---|---|---|---|
2 | 1.50 | 92 | 11% |
x + y = 16 and x - y = 4, so substituting...
x = 4 + y
y + (4 + y) = 16
y + y = 16 - 4
2y = 12, so y = 6
x + 6 = 16, so x = 10
UPDATE: This solution from reader Dave Reynolds is more elegant:
If you add the left and right sides of both equations you get:
2x = 20 --> x = 10
10 + y = 16 --> y = 6
10 + 6 = 16
10 - 6 = 4
QED.
1 B | 2 A | 3 G | 4 E | 5 L | 6 U | 7 R | 8 S | 9 A | 10 O | 11 T | 12 I | 13 S |
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14 I | R | A | Q | I | 15 N | O | E | L | 16 A | H | M | E |
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17 X | P | L | U | S | 18 Y | I | S | S | I | 19 X | T | E | E | N |
20 A | L | E | 21 A | T | E | E | 22 G | A | S |
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23 T | 24 R | 25 I | T | E | S | 26 T | 27 E | N | D | 28 O | R | S | E |
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29 S | O | M | E | 30 Y | E | 31 A | T | S | 32 N | A | Y | S |
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33 O | U | I | 34 T | O | S | S | 35 E | T | D | |||||
36 X | M | 37 I | N | U | S | Y | 38 I | 39 S | F | O | U | 40 R | ||
41 P | O | T | 42 E | T | A | T | 43 A | O | 44 L |
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45 D | 46 A | R | T | 47 M | 48 E | T | A | L | 49 S | T | D | S |
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50 I | D | E | A | 51 M | E | N | 52 S | A | 53 U | T | E | E | D |
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54 O | M | S | 55 R | A | R | 56 E | 57 R | N | A | |||||
58 X | I | S | 59 T | E | N | A | N | 60 D | Y | I | S | 61 S | 62 I | 63 X |
64 I | R | E | D | 65 E | G | O | S | 66 T | I | E | T | O |
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67 N | E | D | S | 68 R | E | S | T | 69 E | S | S | E | X |
Answer summary:
3 unique to this puzzle.
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